This part focuses mainly on three major theoretical methods for studying binding:
These methods help determine:
This is one of the most important experimental techniques in protein chemistry.
The principle is simple:
binding either releases heat or absorbs heat
That heat change is directly measured.
You have:
You inject ligand stepwise into the protein solution.
Each injection gives a heat pulse (peak).
The instrument keeps temperature constant.
So if binding releases heat, the machine compensates.
That compensation is what gets measured.
Yes — this is essentially correct.
Let’s refine it.
A downward peak usually means:
the system released heat (exothermic binding)
Therefore the machine must remove heat to keep temperature constant.
So yes:
ligand binding itself can produce heat
Exactly.
This is common when favorable interactions form:
These release energy.
This is extremely important.
At the beginning:
Large peaks.
Later:
Smaller peaks.
Eventually:
Peaks approach baseline.


This is exactly what your file describes.
This part is very important and your file explains it well.
Even if no protein is present, injecting ligand into buffer can still generate heat because of:
This is called heat of dilution / background heat
So we run a control:
ligand into buffer only
Then subtract it from the experimental signal.
This gives pure binding heat.
This correction is essential.
Excellent question.
This is one of the most important concepts.
After integrating the peaks, you get a sigmoidal binding curve.
The x-axis is usually:
molar ratio = ligand / macromolecule
The midpoint corresponds to:
50% occupancy
That means half the binding sites are occupied.
For a simple 1:1 interaction:
P + L ightleftharpoons PL
the dissociation constant is
K_D = rac{[P]L}{PL}
By definition:
when
P = PL
then
K_D = L
This is exactly the half-saturation point.
So the midpoint corresponds to (K_D).
That is why the file says the midpoint gives the binding constant.
This is why ITC is such a powerful technique.
Unlike many other methods, it gives direct thermodynamics.
From ITC you get:
Then use:
Delta G = RT ln K_D
and
Delta G = Delta H - TDelta S
So:
Delta S = rac{Delta H - Delta G}{T}
This lets you determine entropy too.
This is exactly what your file mentions.
Yes — absolutely correct.
This is one of the limitations.
ITC requires relatively high concentrations because the heat signal must be measurable.
Typical ranges:
Why?
Because the temperature change is tiny.
Often only microcalories.
So enough molecules must bind to produce detectable heat.
This is also why weak interactions can be difficult.
This is another very important theory section.
The idea is:
repeat binding experiments at different temperatures
Then observe how (K_D) changes.
The Van’t Hoff equation is:
ln K = -rac{Delta H}{RT} + rac{Delta S}{R}
If you plot
ln K
against
1/T
you get a straight line.
Slope gives enthalpy.
ln K = -rac{Delta H}{RT} + rac{Delta S}{R}
Excellent question.
For a simple 1:1 binding interaction, yes.
The Van’t Hoff enthalpy should approximately match the experimentally measured enthalpy.
That agreement means:
the model is thermodynamically simple
Usually:
This is exactly what the file says.
This is very important.
If
Delta H_ eq Delta H_
then binding is probably not simple 1:1
Possible reasons:
So the disagreement tells you:
your assumed binding model is too simple
This is a powerful diagnostic tool.
This is a completely different type of method.
Instead of heat, it measures changes in refractive index at a gold surface.
This gives real-time binding kinetics.
Your understanding is close.
Let me refine it.
A thin gold film is used.
At the gold surface there are free electrons.
When polarized light hits at a specific angle, it excites surface plasmons.
These are collective oscillations of electrons.


These electron waves propagate along the surface.
When molecules bind to the surface, the local refractive index changes.
This changes the resonance condition.
The instrument measures the change in reflected light angle/intensity.
That signal is proportional to mass on the surface.
This matches your file very well.
Your steps are mostly correct, but let’s make them precise.
Protein is attached to gold surface.
This is not ligand saturation yet
It is immobilization.
Ligand solution flows across.
Association occurs:
P + L o PL
Signal rises.
This phase gives:
k_
Now ligand flow stops.
Only buffer passes over the surface.
Bound complexes begin to dissociate.
Signal decreases.
This gives:
k_
Then
K_D = rac{k_}{k_}
K_D = rac{k_}{k_}
This gives binding strength / affinity.
So yes, your conclusion is correct.
The main correction is:
first immobilize macromolecule then flow ligand then wash with buffer
Not “saturate macromolecule with ligand” as the first step.
This is a very important comparison.
This is extremely useful because two ligands can have same (K_D) but different kinetics.
Example:
same affinity, but one dissociates slowly.
That often means stronger practical inhibition.
Measures:
heat released or absorbed during binding
Best for:
thermodynamics
Measures:
temperature dependence of binding constant
Best for:
model validation and enthalpy estimation
Measures:
real-time association and dissociation on gold surface
Best for:
kinetics + affinity
You were mostly on the right track.
Main refinements: